Question

what are the zeroes of the function f(x)= 3x^2+9x+6 / 3x+3

Answer 1

u just need to find zeroes of num

Answer 2

\[(3x^2+9x+6)=(x+2)(3x+3)\] equating this to zero will give you zeroes

Answer 3

would the zeroes be -2, -3?

Answer 4

(x+2)(3x+3)=0
x=-2, -1, not sure tho :)

Answer 5

im sorry i mean -2

Answer 6

Okay thank you!!

Answer 7

yeah x=-2 and -1

Answer 8

(:

Answer 9

you need to leave the variable x by it'self

Answer 10

okay thanks!

Answer 11

Erica when you factored the trinomial, you forgot to rewrite the fraction as

\[\frac{((x+2)(3x+3)}{(3x+3)}\]

Had you done that, you would have realized that \(\large\frac{(3x+3)}{(3x+3)}\) cancels leaving you with x + 2 only, which means we would only need the zero for (x+2) which is x = -2

Answer 12

@erica.d

Answer 13

Especially since x = -1 is undefined

Answer 14

@Hero thanks !! i just thought about the factors because of what value of numerator will be zero, hence i will have zero of that function ...