A diver is on the 10m platform, preparing to perform a dive. the diver's height above the water, in metres, at time t can be modelled using the equation : h(t)= -4.9(t)^2 + 2t + 10.. Estimate the rate at which the diver's height above the water is changing as the diver enters the water. be sure to include at least 3 intervals from booth sides in your table. I think its instantaneous rate of change..
can you find t when h(t) =0?
its 1.65s aprox
ok so, maybe use intervals like t= 1.15...1.65 ; t=1.55...1.65 and t= 1.64...1.65 ?
thank you!!
(h(1.65) - h(1.15) )/ (.5) (h(1.65) - h(1.55) ) / (.1) (h(1.65) - h(1.64) ) / (.01)
I'm guessing that's what they want you to do... then evidently, the same for the 'other side' ( h(2.15) - h(1.65) ) / (.5) (h(1.75) - h(1.65) ) / (.1) etc.
yeahh, the answer is approx. 14m/s which is correct! thank you so much.. been stuck on this question for awhile:P
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