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OpenStudy (anonymous):
Help!!!! Determine whether the following integrals converge, and if they do, to what. Integral from 4 to infinity (1/x^3) dx
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OpenStudy (anonymous):
\[\lim_{n \rightarrow \infty} \int\limits_{4}^{n} \frac{ 1 }{ x ^{3} }\]
OpenStudy (anonymous):
does that help or do you need more...?
OpenStudy (anonymous):
|dw:1348432240384:dw|
OpenStudy (anonymous):
i don't know how to do it
OpenStudy (anonymous):
evaluate the integral
=-1/(2x^2)
plug in n and 4
-1/(2n^2) - -1/(2(4)^2)
find the limit as n-> infinity
(hint: this one is super easy)
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OpenStudy (anonymous):
clear on that?
OpenStudy (anonymous):
questions? comments? concerns?
OpenStudy (anonymous):
I need to see you do it out please?
OpenStudy (anonymous):
i got -1/32 ...but i think its suppose to be positive?
OpenStudy (anonymous):
- - 1/(2(4)^2)
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OpenStudy (anonymous):
why is there 2 minuses?
OpenStudy (anonymous):
n
-1/(2x^2) | = -1/(2n^2) - -1/(2*4^2)
4
OpenStudy (anonymous):
4 is the lower limit of integration, n is the upper limit of integration
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