Question

Can anyone help with synthetic division please........
(3x^3+6x^2+8x+6x)/(x-1/2)............. I don't understand synthetic division, or longhand division please please please help me

Answer 1

Check the ast term. Is it 6 or 6x?

Answer 2

its 6

Answer 3

I've been working this problem for 30 min now

Answer 4

ok. First arrange the coefficients of the given polynomial in descending order
Note: for example: 5x^2 - 1 will have the coefficient 5 0 -1

Answer 5

Next solve the given divisor for its zero

Answer 6

this is the answer that I get for the problem 3x^2+7x+15/2+13/4(x-1/2)

Answer 7

So (3x^3 + 6x^2 + 8x + 6) /(x -1/2) will become the following:
x - 1/2 = 0 will give x = 1/2
Coefficient for 3x^3 + 6x^2 + 8x + 6 will be 3 6 8 6
Synthetic division will now begin as follows:
1/2 | 3 6 8 6
| 3/2 15/4 47/8
3 15/2 47/4 95/8
Thus, (3x^3 + 6x^2 + 8x + 6) = (3x^2 + (15/2)x + (47/4))(x -1/2) + (95/8)

Answer 8

it's have to be written as a fraction at the end

Answer 9

I am typing it out well for you. Will do it as an attachment.

Answer 10

this is what I get when I check the answer......... Remember to place the remainder over the divisor, them simplify so that there is no fraction in the numerator

Answer 11

ok

Answer 12

Can you check on it now?