Question

√35 OVER √38

Do i just multiply both sides by √38 then simplify?

Answer 1

i was told you cannot have a square root on the denominator and to get rid of it, you multiply both sides by the denominator.

Answer 2

@maherman97 you are correct

Answer 3

so it would be √1330 OVER √1444

Answer 4

well, you can simplify the denominator here

Answer 5

because remember you got to it by doing this:\[\frac{\sqrt{35}}{\sqrt{38}}=\frac{\sqrt{35}}{\sqrt{38}}\times\frac{\sqrt{38}}{\sqrt{38}}=\frac{\sqrt{35*38}}{\sqrt{38*38}}\]

Answer 6

so what is \(\sqrt{38*38}=\sqrt{38^2}=?\)

Answer 7

@micahwood50 that is not how radicals are simplified. @maherman97 has the correct approach for this type of problem

Answer 8

@maherman97 what is \(\sqrt{38*38}=\sqrt{38^2}=?\)

Answer 9

i.e. what is the square root of something squared?

Answer 10

more generally, what is \(\sqrt{x^2}=?\)

Answer 11

SOO SORRY! its 38! so i would have √1330 OVER 38???

Answer 12

yes - that is the correct answer. :)

Answer 13

and i would simplify?

Answer 14

that is now in its simplest formas \(\sqrt{1330}\) cannot be simplified any further

Answer 15

well what about like 2 and 665

Answer 16

and so on

Answer 17

\[1330=2\times5\times7\times19\]all of which are prime number, so the square root cannot be simplified any further

Answer 18

ohhh OK THANKS SOO MUCH!

Answer 19

yw :)

Answer 20

i have another!

Answer 21

<-- please post each question separately on the left.