Composition help
Composition of functions, right?
\[(f0g)(x)\] \[F(x) =4/(x+1)\] \[g(x)=4/x\]
yes
Hint: (f o g)(x) = f(g(x))
i got that im lost on what to do after that
i never really liked improper fractions
We don't know if the fraction is proper or improper because we don't know the value of x
But anyway, f(g(x)) means to insert the entire expression for g(x) into the input for f(x)
So you'll end up with: F(4/x) = 4/((4/x) + 1) But of course, now you have to simplify that
Good luck simplifying that.
thats want im trying to do, would i multiply the denominator to the other side, and then find x, or would i flip the denominator and multiply it to the top?
Let me show you how to simplify it. We ended up with \[f\left(\frac{4}{x}\right) = \frac{4}{\frac{4}{x} + 1}\] So lets concentrate on simplifying the right side.
First to make things a little easier to digest, lets re-write the right side as \[4 \div \left(\frac{4}{x} + 1\right)\]
Now, remembering PEMDAS, lets simplify whatever is inside the parentheses first. We need to combine 4/x and 1, so re-write 1 = x/x : \[4 \div \left(\frac{4}{x} + \frac{x}{x}\right)\]
Combining that, we get \[4 \div \left(\frac{4+x}{x}\right)\] Now we need to take the reciprocal of the fraction to change the division to a multiplication: \[4 \dot\ \left(\frac{x}{x+4}\right)\]
Thus we are left with \[f\left(\frac{4}{x}\right) = \frac{4x}{x+4}\]
thank you
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