Mathematics
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OpenStudy (anonymous):
A circle whose center is at (6,8) passes through the
origin, Which of the following points is NOT on the
circle?
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hartnn (hartnn):
can u find the equation of circle ?
OpenStudy (anonymous):
well
OpenStudy (anonymous):
I use slope formula
OpenStudy (anonymous):
8-0/6-0=8/6
OpenStudy (anonymous):
what's the equation of a circle?
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OpenStudy (anonymous):
I forgot...
hartnn (hartnn):
standard form :
(x-h)^2 + (y-k)^2 = r^2
centre = (h,k)
radius =r
OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
so I could not just use distance formula?
hartnn (hartnn):
nopes
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OpenStudy (anonymous):
well, its like distance formula except it has r squared in it
OpenStudy (anonymous):
and no sq. root
OpenStudy (anonymous):
64+64=128=r sq.
hartnn (hartnn):
put (h,k)=(6,8) in that
OpenStudy (anonymous):
sq. root 128
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OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
whose center is at 6,8
OpenStudy (anonymous):
I thought the center was at the origin
OpenStudy (anonymous):
64+64=r sq.
OpenStudy (anonymous):
r= sq. root 128
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OpenStudy (anonymous):
right?
OpenStudy (anonymous):
what next?
hartnn (hartnn):
nopes, u did not put h,k = 6,8 in this.
(x-h)^2 + (y-k)^2 = r^2
OpenStudy (anonymous):
yeah I did
OpenStudy (anonymous):
(0-8) quantity squared=64
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OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
64+36=r sq.
OpenStudy (anonymous):
r=10
OpenStudy (anonymous):
l
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
so the radius equals 10
OpenStudy (anonymous):
(10,0)?
OpenStudy (anonymous):
or just 10?
OpenStudy (anonymous):
so (16,8) is a possibility
OpenStudy (anonymous):
so is (4,-8)
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hartnn (hartnn):
radius is 10, but i would say u still did NOT put h,k = 6,8 in
(x-h)^2 + (y-k)^2 = r^2
OpenStudy (anonymous):
as well as (6,8)
OpenStudy (anonymous):
I mean
OpenStudy (anonymous):
(6,-2)
OpenStudy (anonymous):
so we have two answers left, (12,0) and (-2,12)
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OpenStudy (anonymous):
where did I go wrong?
OpenStudy (anonymous):
36+64=100
OpenStudy (anonymous):
r=10
OpenStudy (anonymous):
I plugged the numbers in the formula
hartnn (hartnn):
can i request u something ?
please put h,k = 6,8 in
(x-h)^2 + (y-k)^2 = r^2
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OpenStudy (anonymous):
h=36
OpenStudy (anonymous):
after quantity squared
OpenStudy (anonymous):
k=64 quantity squared
OpenStudy (anonymous):
wait a minute
OpenStudy (anonymous):
ahh
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OpenStudy (anonymous):
(-2-8) sq. +(12-6) sq=r sq.
OpenStudy (anonymous):
D. is incorrect
OpenStudy (anonymous):
is that right?
hartnn (hartnn):
let me put h,k = 6,8 in
and r=10
(x-h)^2 + (y-k)^2 = r^2
put h,k = 6,8 in
(x-6)^2 + (y-8)^2 = 10^2
did u get this ?
OpenStudy (anonymous):
yeah
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
r=10
OpenStudy (anonymous):
D. is incorrect because r does not equal 10
OpenStudy (anonymous):
so D. is the answer for the problem
OpenStudy (anonymous):
ty for teaching me that formula
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OpenStudy (anonymous):
It will be useful for me in the future
hartnn (hartnn):
yes, it will be
welcome :)