Question

Ok Calculus Product Rule f(x)=secx tanx

Answer 1

you can use \((fg)'=f'g+g'f\) with \(f(x)=\sec(x), f'(x)=\sec(x)\tan(x), g(x)=\tan(x), g'(x)=\sec^2(x)\)

Answer 2

d/dx(sec(x) tan(x)) = sec(x) (tan^2(x)+sec^2(x))

Answer 3

I got something completely different

Answer 4

but thank you guys for trying !

Answer 5

What did you get?

Answer 6

i got secx(sex^2x)= tanx (secxtanx)

Answer 7

it's product rule therefore I exchanged the problem with their corresponding identities

Answer 8

Your truing to find the derivative right?

Answer 9

yes i'm pretty sure I am math isn't my strongest subject

Answer 10

You cant write the answer like that then...

Answer 11

the directions say use the product rule

Answer 12

Yea but You have to have f '(x)= blah

Answer 13

as the answer

Answer 14

oh ok so if i put the f(x) then it would be correct ?

Answer 15

Watch..