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Mathematics 22 Online
OpenStudy (anonymous):

Can someone please help with summation

OpenStudy (anonymous):

|dw:1348458971513:dw|

OpenStudy (anonymous):

write the term of the series and find their sum

OpenStudy (anonymous):

replace \(k\) by 1 get \((1+6)^2=49\) put a plus sign replace \(k\) by 2, get \((2+6)^2=64\) another plus sign lather, rinse, repeat until you replace \(k\) by 4, then stop \(49+64+...\)

OpenStudy (anonymous):

so the sum is 49

OpenStudy (anonymous):

not at all

OpenStudy (anonymous):

the first term of the sum is 49

OpenStudy (anonymous):

so 49+64+79+94

OpenStudy (anonymous):

How high up do I go

OpenStudy (anonymous):

where did the 79 come from?

OpenStudy (anonymous):

15 from 64 like the 64 is from 49 wrong idea

OpenStudy (anonymous):

it does have four terms, since you have \(k=1\) then \(k=2\) then \(k=3\) then \(k=4\) oh yeah wrong idea

OpenStudy (anonymous):

lol sorry I hate this

OpenStudy (anonymous):

that is because it is confusing the first time you see it, but believe me you are just learning how to read it is really nothing once you know what it says the sigma is a big fat plus sign, that is all

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

you start at \(k=1\) and get the first term which is \((1+6)^2=7^2=49\) and then comes a plus sign, so you have \(49+\) so far now you replace \(k\) by 2 and get \((2+6)^2=8^2=64\) and another plus, so now you are up to \[49+64+\]

OpenStudy (anonymous):

again you replace \(k\) by 3 and get \((3+6)^2=9^2=81\) giving us \[49+64+81+\]

OpenStudy (anonymous):

then 100

OpenStudy (anonymous):

and finally you replace \(k\) by 4 giving \((4+6)^2=10^2=100\) and now we are done because of the 4 on top of the sigma we get \[49+64+81+100\] yes you are right it is 100

OpenStudy (anonymous):

so its asking for the terms of the series using commas to seperate answers as needed so it would be 46,64,81,100

OpenStudy (anonymous):

then do I add all them up for the sum

OpenStudy (anonymous):

now you add this mess up believe me this is not so bad, math gets much harder it is just a matter of learning how to read it

OpenStudy (anonymous):

so the sum is 291

OpenStudy (anonymous):

yes, terms are \(49,64,81,100\) and sum is \[\sum_{k=1}^4(k+6)^2=49+64+81+100\] whatever that is

OpenStudy (anonymous):

291

OpenStudy (anonymous):

ok i believe you i can't add

OpenStudy (anonymous):

lmao

OpenStudy (anonymous):

actually i don't believe you how can it end in a 1?

OpenStudy (anonymous):

294

OpenStudy (anonymous):

that is why god invented calculators on the eighth day

OpenStudy (anonymous):

ty for the help

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

lmao

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