Can someone please help with summation
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write the term of the series and find their sum
replace \(k\) by 1 get \((1+6)^2=49\) put a plus sign replace \(k\) by 2, get \((2+6)^2=64\) another plus sign lather, rinse, repeat until you replace \(k\) by 4, then stop \(49+64+...\)
so the sum is 49
not at all
the first term of the sum is 49
so 49+64+79+94
How high up do I go
where did the 79 come from?
15 from 64 like the 64 is from 49 wrong idea
it does have four terms, since you have \(k=1\) then \(k=2\) then \(k=3\) then \(k=4\) oh yeah wrong idea
lol sorry I hate this
that is because it is confusing the first time you see it, but believe me you are just learning how to read it is really nothing once you know what it says the sigma is a big fat plus sign, that is all
ok
you start at \(k=1\) and get the first term which is \((1+6)^2=7^2=49\) and then comes a plus sign, so you have \(49+\) so far now you replace \(k\) by 2 and get \((2+6)^2=8^2=64\) and another plus, so now you are up to \[49+64+\]
again you replace \(k\) by 3 and get \((3+6)^2=9^2=81\) giving us \[49+64+81+\]
then 100
and finally you replace \(k\) by 4 giving \((4+6)^2=10^2=100\) and now we are done because of the 4 on top of the sigma we get \[49+64+81+100\] yes you are right it is 100
so its asking for the terms of the series using commas to seperate answers as needed so it would be 46,64,81,100
then do I add all them up for the sum
now you add this mess up believe me this is not so bad, math gets much harder it is just a matter of learning how to read it
so the sum is 291
yes, terms are \(49,64,81,100\) and sum is \[\sum_{k=1}^4(k+6)^2=49+64+81+100\] whatever that is
291
ok i believe you i can't add
lmao
actually i don't believe you how can it end in a 1?
294
that is why god invented calculators on the eighth day
ty for the help
yw
lmao
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