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factor the expression completely: 16x^4-16
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The greatest factor of that expression is 16: \[16(x^4 - 1)\] Can you factor the expression in parenthesis?
(x^2)^2-1^2?
What about: \[(x^2 - 1)(x^2 + 1)\] ?
true.. 16(x^2-i)(x^2+1) you can still factor out the (x^2-1) right?
Right (I'm guessing the "i" is a typo and you meant 1). So the (x^2 - 1) can be factored again.
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yeah sorry.. haha but that factors out to be (x-1)(x+1) so that gives you 16(x-1)(x+1)(x^2+1)
You got it. That's completely factored.
cool thanks! :D
No prob.
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