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Mathematics 17 Online
OpenStudy (anonymous):

use the quotient rule. xsinx+cosx Plz hlp.

OpenStudy (anonymous):

derivative or integrate?

OpenStudy (anonymous):

derivative

OpenStudy (anonymous):

why would you use quotient rule?

OpenStudy (anonymous):

thats a product rule

OpenStudy (anonymous):

noooooo idea, that's what it says on my homework :/

OpenStudy (anonymous):

you ned to use the product rule, is an easy one \[\frac{ d }{ dx}\ xsinx + \frac{ d }{ dx} cosx\] note : \[\[\frac{ d }{ dx}[f(x).g(x)] = f(x) \times \frac{ d }{ dx}g(x) + g(x) \times \frac{ d }{ dx}f(x)\]

OpenStudy (anonymous):

yeah I know how to use the product rule, it just tripped me out that the directions ask for the quotient rule. thank you.

hero (hero):

Suggestion: A product can be re-written as a quotient, thus enabling the use of the quotient rule as the given problem requires.

OpenStudy (anonymous):

how would you do that?

OpenStudy (anonymous):

good catch Hero, but thats just pain to use it when the problem is clearly product rule, weird.

hero (hero):

It's a pain, however, I can remember all sorts of problems that could be solved using much simpler methods, yet they asked and required that I do them using very specific, well defined and established methods that were seemingly written in stone with regard to which I could not object.

OpenStudy (anonymous):

so i just use product rule?

OpenStudy (anonymous):

ya you need to use the product rule ;)

hero (hero):

In my humble opinion, I highly recommend that you do it using the quotient rule.

OpenStudy (anonymous):

I have no idea how to do that though.

hero (hero):

Write g(x) as the denominator the fraction

OpenStudy (anonymous):

its better you use product rule, in product rule , you will get the answer in 2 steps whereas you need to solve many steps in order to solve using the quotient rule :O

OpenStudy (anonymous):

ok, so it would be xsinx/cosx?

hero (hero):

No, it wouldn't be that, because then you would be changing an addition into a division which is not allowed under any circumstance.

hero (hero):

If you were to use the product rule, what would you choose for f(x) and g(x)

hero (hero):

Whatever you would choose for g(x), write that as the denominator of your fraction.

OpenStudy (anonymous):

xsinx for f and cosx for g?

hero (hero):

So you're going to apply the product rule to an addition?

OpenStudy (anonymous):

can you explain what f and g would be and why? I've never done that before.

OpenStudy (anonymous):

okay f(x)= x g(x) = y if you find the derivative of f(x) it is '1' and the derivatiove of g(x)= y = 'dy/dx' now you can substitute the values in the formula i mentioned above ;)

hero (hero):

@lizlozada, you mean to tell me it isn't obvious what the product is ? And that when using the product rule, the first thing being multiplied would be f(x) and the second thing being multiplied with the first would g(x)?

OpenStudy (anonymous):

\[f(x) = x , \frac{ d }{ dx }f(x) = 1, g(x)= \sin x , \frac{ d }{ dx }\sin x= \cos x\]

OpenStudy (anonymous):

no, never mind, I'll ask my teacher tomorrow, thanks for your help.

OpenStudy (anonymous):

thats the differentiation of xsinx and you can differentiate cosx easily ;) so here you get the answer ;)

OpenStudy (anonymous):

\[(x \times cosx + sinx \times 1 )- (sinx)\] hence you can solve further ;)

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