use the quotient rule. xsinx+cosx Plz hlp.
derivative or integrate?
derivative
why would you use quotient rule?
thats a product rule
noooooo idea, that's what it says on my homework :/
you ned to use the product rule, is an easy one \[\frac{ d }{ dx}\ xsinx + \frac{ d }{ dx} cosx\] note : \[\[\frac{ d }{ dx}[f(x).g(x)] = f(x) \times \frac{ d }{ dx}g(x) + g(x) \times \frac{ d }{ dx}f(x)\]
yeah I know how to use the product rule, it just tripped me out that the directions ask for the quotient rule. thank you.
Suggestion: A product can be re-written as a quotient, thus enabling the use of the quotient rule as the given problem requires.
how would you do that?
good catch Hero, but thats just pain to use it when the problem is clearly product rule, weird.
It's a pain, however, I can remember all sorts of problems that could be solved using much simpler methods, yet they asked and required that I do them using very specific, well defined and established methods that were seemingly written in stone with regard to which I could not object.
so i just use product rule?
ya you need to use the product rule ;)
In my humble opinion, I highly recommend that you do it using the quotient rule.
I have no idea how to do that though.
Write g(x) as the denominator the fraction
its better you use product rule, in product rule , you will get the answer in 2 steps whereas you need to solve many steps in order to solve using the quotient rule :O
ok, so it would be xsinx/cosx?
No, it wouldn't be that, because then you would be changing an addition into a division which is not allowed under any circumstance.
If you were to use the product rule, what would you choose for f(x) and g(x)
Whatever you would choose for g(x), write that as the denominator of your fraction.
xsinx for f and cosx for g?
So you're going to apply the product rule to an addition?
can you explain what f and g would be and why? I've never done that before.
okay f(x)= x g(x) = y if you find the derivative of f(x) it is '1' and the derivatiove of g(x)= y = 'dy/dx' now you can substitute the values in the formula i mentioned above ;)
@lizlozada, you mean to tell me it isn't obvious what the product is ? And that when using the product rule, the first thing being multiplied would be f(x) and the second thing being multiplied with the first would g(x)?
\[f(x) = x , \frac{ d }{ dx }f(x) = 1, g(x)= \sin x , \frac{ d }{ dx }\sin x= \cos x\]
no, never mind, I'll ask my teacher tomorrow, thanks for your help.
thats the differentiation of xsinx and you can differentiate cosx easily ;) so here you get the answer ;)
\[(x \times cosx + sinx \times 1 )- (sinx)\] hence you can solve further ;)
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