Question

What is the solution set of |x – 4| + 7 = 4?




What is the solution set of |2x – 3| – 10 = –1?





What are the anwsers to these 2 problems & how do you get em?

Answer 1

1. for 1st problem, subtract 7 from both sides, what u get ?

Answer 2

-(x-4) +7 = 4 and (x-4) + 7 = 4 ... thats for the first on eand then solve....

Answer 3

find x for both equations adn you have your two answers... then do the same thing for the second question

Answer 4

so the 1st ones no solution?

Answer 5

I really have no idea about any of this stuffff?

Answer 6

no there are two answers... one for each equation i just made

Answer 7

|a|=b
can be written as
a=b OR a=-b
and the two solutions for a are b,-b
Apply same principle here.

Answer 8

I'll solve the first one
|x – 4| + 7 = 4?
Okay, you're going to start by isolating the absolute value, so:
|x-4| + 7- 7= 4 - 7
and you're left with
|x-4|=-3

Okay, so consider the positive an negative cases:
x-4=-3 OR x-4=3
Solve for x for each so:
x-4=-3
x=1

AND
x-4=3
x=7

So x=-3 and x=7

Answer 9

lol. there is NO SOLUTION for first :P

Answer 10

So the first step to solving these is to get the absolute value by itself?

& wait what do u mean theres no solution for the 1st one?????

Answer 11

@melbel u know why ?

Answer 12

YES! get the absolute value by itself.

Answer 13

|x-4|=-3 for first right ?

Answer 14

okay cool thanks! & i do that by subtracting/multiplying..... from both side to get that?
& y is #one no solution?

Answer 15

the meaning of |a| is that a *cannot* take negative values.
u have
|x-4|=-3
is this possible ?

Answer 16

i'd no? because there both negative but 2 negatives = a positive right?

Answer 17

*say

Answer 18

yes that correct

Answer 19

i would say |..*anything*..| cannot be negative
so |x-4| cannot be negative.(but here its -3)
hence there is no solution for first.

Answer 20

Duh, hartnn! I didn't see that. I should be beaten. Yeah, no solution! I'd like to say that it's because it's 2 AM, but no, I should I noticed that right off the bat. Hartnn is right.

Answer 21

thanks for that tip. so basically when you first see a problem and u see that there is a negative in the absolute values bar then u already know that its no solution?

Answer 22

No, if an absolute value (after being isolated) is equal to a negative.

Answer 23

as u rightly mentioned, first get the absolute value by itself
if its negative, then no solution.

Answer 24

So |x+4| = -3 has no solution because the absolute value cannot be negative.

Answer 25

But |x-4| = 3 has a solution, because the 3 is positive.

Answer 26

go for 2nd problem now, add 10 to both sides.

Answer 27

oh okay! thank yall so much! yalll have no idea how muched u just helped me! i dont get math at allll its not my subject!

Answer 28

You can look at it at the very basic level of absolute values, so:
What is the absolute value of:
|7|
it's 7
What about |-7|
Still 7. You can't get a negative.

Answer 29

|2x-7|=-1

Answer 30

thats not the correct way, keep |2x-3| as it is
|2x-3|-10+10=-1+10
|2x-3| +0=9
|2x-3|=9
got this ?

Answer 31

|2x – 3| – 10 = –1
|2x-3| = 9

So 2x-3 = 9 OR 2x-3 = -9
First case: 2x-3=9
2x=12
x=6

Second case: 2x-3=-9
2x=-6
x=-3

So x=6 OR x=-3

Answer 32

correct

Answer 33

thats right @melbel ,but isn't it better that @CIERA1338 tries that on her own.?....

Answer 34

no problem, i hope she doesn't *look* through your solution and try herself...

Answer 35

thank you all so much! but hartnn is right! It's just hard for me to work out the problems i get so confused easily in math...

Answer 36

thank you all again! (: