Could I get some help factorizing the following expression?

-6x^2-16x+32

Question

Could I get some help factorizing the following expression?

-6x^2-16x+32

waleed_imtiaz · Answer

6x^2+16x-32=0
OKay.... NOw...... 
6x^2+24x-8x-32=0
6x(x+4)-8(x+4)=0.......... So, x=-4 or x=4/3

anonymous · Answer

$$-2(3x^{2} +8x -16)$$$$-2(3x^{2}+ 12x - 4x -16)$$$$-2[(3x-4)(x+4)]$$

anonymous · Answer

Thank you. I still have some trouble understanding the first step though.. where does 24x-8x come from (waleed).. or 12x-4x (curiusshubham)

waleed_imtiaz · Answer

see @IHGR-PreIB  we have to make the pairs whose sum or difference should equal to the middle term which consist power of x as one........ ANd these two pairs should also satisfy the product of 1st and last term co-efficients...... For example..... 
6x^2+16x-32=0... Its like this.. Okay....... NOw the product of 1st and last term co-efficients =6(-32)=192..... so I made the pairs as 24 and 8... because when u multiply these..... 24*(-8)=-192.... and If U add and subtract them u will get 16x..... now U got it ?

anonymous · Answer

I think I do. Thx a lot

waleed_imtiaz · Answer

My pleasure.....!