Question

can someone explain to me how to solve for x in \frac{1}{x-1}-\frac{1}{2x+1}=0

Answer 1

add 1/(2x+1) to both sides.

Answer 2

\(\huge \frac{1}{x-1}-\frac{1}{2x+1}+\frac{1}{2x+1}=0+\frac{1}{2x+1} \)
what remains on left side ?

Answer 3

\[\frac{ 1 }{ x-1? } remains on the \left\]

Answer 4

nursingmom2 you need to cooperate anything not just gett the right answers

ok ?

Answer 5

yes, thats correct.
so u have
\(\huge \frac{1}{x-1}=\frac{1}{2x+1}\)
now i will give u hint :
if
\(\huge \frac{1}{a}=\frac{1}{b} \quad \text {then a=b}\)
can u simplify further ?

Answer 6

yes, if you have x-1=2x+1, you could subtract 1 from both sides giving you x-2=2x, then further simplify by subtracting x from both sides which would give you -2=x

Answer 7

you are absolutely correct!
good work :)

Answer 8

thank you

Answer 9

welcome :)