can someone explain to me how to solve for x in \frac{1}{x-1}-\frac{1}{2x+1}=0

Question

hartnn · Answer

add 1/(2x+1) to both sides.

hartnn · Answer

$\huge \frac{1}{x-1}-\frac{1}{2x+1}+\frac{1}{2x+1}=0+\frac{1}{2x+1} $
what remains on left side ?

anonymous · Answer

$$\frac{ 1 }{ x-1? } remains on the \left$$

jhonyy9 · Answer

nursingmom2 you need to cooperate anything not just gett the right answers 

ok ?

hartnn · Answer

yes, thats correct.
so u have 
$\huge \frac{1}{x-1}=\frac{1}{2x+1}$
now i will give u hint :
if 
$\huge \frac{1}{a}=\frac{1}{b} \quad \text {then a=b}$
can u simplify further ?

anonymous · Answer

yes, if you have x-1=2x+1, you could subtract 1 from both sides giving you x-2=2x, then further simplify by subtracting x from both sides which would give you -2=x

hartnn · Answer

you are absolutely correct!
good work :)

anonymous · Answer

thank you

hartnn · Answer

welcome :)