Question

solve for x: 3x^2 + 9x +4=0
please show all work...thanks

Answer 1

Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two roots of x are:
\(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 2

so then x= -0.5425 and x= -2.4575

Answer 3

Apply the method of completing the squares

Answer 4

your answer is correct @stardust3829

Answer 5

3x^2 + 9x +4=0
Divide through by 3: x^2 + 3x + 4/3 = 0
x^2 + 3x = -4/3
x^2 + (3/2)x + (3/2)^2 = -4/3 + (3/2)^2
(x + 3/2)^2 = -4/3 + 9/4
(x + 3/2)^2 = 11/12
(x + 3/2) = sqrt(11/12)
x = - 3/2 (+/-) sqrt(11/12)

Answer 6

This will give x = -0.5426, -2.4574