Question

Show that xz < yz whenever x > y and z > 0.

Answer 1

that is never true.

Answer 2

There is a way out

Answer 3

z should be negative and not z > 0

Answer 4

so..what's the question?

Answer 5

Show that xz < yz whenever x > y and z < 0.

??

Answer 6

but u wrote z>0

Answer 7

Sorry for the inconvenience.
The question is Show that xz < yz whenever x > y and z < 0.

Answer 8

x > y

so multiply z to both sides

xz > yz

since z is negative...

-xz > -yz

divide both sides by -1

xz < yz

right?

Answer 9

I need an analytical solution

Answer 10

wasn't that analytical?

Answer 11

it seems algebraic to me

Answer 12

sure