Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

9 – c < 2 c

OpenStudy (anonymous):

-c < -7 therefore c< 7

hartnn (hartnn):

cannot be determined

OpenStudy (theviper):

9-c<2 Subtract 9 9-9-c<2-9 -c<-7 c>-7

hartnn (hartnn):

nopes @miteshchvm

OpenStudy (anonymous):

-c < -7 therefore if we multiply be -1 we get c > 7 i ought to correct myself ;)

OpenStudy (anonymous):

Which graph shows the solution of 9 – c < 2 or –3c > 15? thats the question for my homework

OpenStudy (anonymous):

lol m confused by this midnight study! i really nee sleep! :D

OpenStudy (anonymous):

what would the graph look like thats basically what its asking

OpenStudy (anonymous):

@TheViper and @hartnn how did you prove c > -7 !? its totally wrong as per i observed the solution, i suggest you to look at it once again

OpenStudy (anonymous):

would the arrows on the graph be like <------ ------> or o-----------o

OpenStudy (nubeer):

well c > 7

OpenStudy (theviper):

if -c<-7 then c>-7

OpenStudy (nubeer):

and arrows would be like the second one.

OpenStudy (anonymous):

o---------------o

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

@TheViper whats the logic in that? you can't change one sign. you need to change it for whole function

OpenStudy (nubeer):

when we remove negative its basically multiply by -1 and the equality signed is reversed.

OpenStudy (nubeer):

@BarbieGurl yes right.. we use hollow circles when < and filled circles for <= or =>

OpenStudy (anonymous):

-c < -7 -(-c) > -(-7) c > 7 thats it!! XD

OpenStudy (anonymous):

\[9-c <2\] \[-c <2-9\] \[-c <-7\] \[-(c)<-7\] \[c >-7/-1\] \[c >7\]

OpenStudy (anonymous):

@BarbieGurl you just go to this site and place your question ;) http://calculator.tutorvista.com/math/452/inequality-calculator.html# thats better

OpenStudy (anonymous):

|dw:1348483071489:dw| so wait would it be like that or empty circles?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!