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Mathematics 15 Online
OpenStudy (anonymous):

Three equal circles of radius r = 1cm are tangent to each other as shown in the picture. Find the area of the shade region.

OpenStudy (anonymous):

OpenStudy (anonymous):

You could connect the circle centers to form an equilateral triangle. Then find the area of the triangle. Each corner of the triangle makes a 60 degree angle from the center of the circle, so the "pie" slice inside the circle is 1/6 of the circle area. The area shaded is the equilateral triangle's area minus the 3 pie shaped pieces of the circles.

OpenStudy (anonymous):

You mean like this

OpenStudy (anonymous):

Right

OpenStudy (anonymous):

|dw:1348501549381:dw|

OpenStudy (anonymous):

Then what is the answer?

OpenStudy (anonymous):

nw it is a equilateral triangle....ie all angles are 60

OpenStudy (anonymous):

So, you need the area of that triangle with side lengths = 2 x radius = 10

OpenStudy (anonymous):

Ok you get it here is the answer\[A _{region}=A_{circle}-A_{\triangle}\] \[A _{region}=3{\pi}r^{2}-\frac{ 1 }{ 2 }(2r)^{2}\sin(60^{o})\] \[A _{region}=3{\pi}-\frac{ 1 }{ 2 }\times4\times \frac{ \sqrt{3} }{ 2 }\]Thus the answer is \[A _{region}=(3{\pi}- \sqrt{3})cm^{2} \]

OpenStudy (anonymous):

ARea shaded = Area of Triangle - 3 * minor segment

OpenStudy (anonymous):

|dw:1348501747222:dw|

OpenStudy (anonymous):

nw u knw the angle.....u have find the are of minor segment

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