Three equal circles of radius r = 1cm are tangent to each other as shown in the picture. Find the area of the shade region.
You could connect the circle centers to form an equilateral triangle. Then find the area of the triangle. Each corner of the triangle makes a 60 degree angle from the center of the circle, so the "pie" slice inside the circle is 1/6 of the circle area. The area shaded is the equilateral triangle's area minus the 3 pie shaped pieces of the circles.
You mean like this
Right
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Then what is the answer?
nw it is a equilateral triangle....ie all angles are 60
So, you need the area of that triangle with side lengths = 2 x radius = 10
Ok you get it here is the answer\[A _{region}=A_{circle}-A_{\triangle}\] \[A _{region}=3{\pi}r^{2}-\frac{ 1 }{ 2 }(2r)^{2}\sin(60^{o})\] \[A _{region}=3{\pi}-\frac{ 1 }{ 2 }\times4\times \frac{ \sqrt{3} }{ 2 }\]Thus the answer is \[A _{region}=(3{\pi}- \sqrt{3})cm^{2} \]
ARea shaded = Area of Triangle - 3 * minor segment
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nw u knw the angle.....u have find the are of minor segment
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