Question

find the derivative of the function.
y=(x^2-3x+2)/(x^7-2)

Answer 1

I did that, but my answer is not like the answer choices.

Answer 2

sorry my answer was slightly wrong there

Answer 3

\[\frac{d}{dx}\frac{f(x)}{g(x)} = \frac{f'(x)g(x) - g'(x)f(x)}{(g(x))^2}\]

Answer 4

\[f(x) = x^2 - 3x + 2\] so\[f'(x) = 2x - 3\]

and \[g(x) = x^7 - 2\] so\[g'(x) = 7x^6\]

Answer 5

ok I did that

Answer 6

\[\frac{d}{dx} \frac{x^2 - 3x + 2}{x^7 - 2} = \frac{(2x - 3)(x^7 - 2) - 7x^6(x^2 - 3x + 2)}{(x^7 - 2)^2}\]

Answer 7

now we probably have to see if it can be simplified

Answer 8

on my answer choices i have to end up with a x^8 i dont see how i can get that

Answer 9

on the top?

Answer 10

is it a -5x^8

Answer 11

yes how did you get that?

Answer 12

did you get my earlier answer? just multiply out the top and collect like terms

Answer 13

i did and i still end up with just x^7

Answer 14

double check your multiplication to make sure you haven't made a silly mistake :)

Answer 15

ok thank you