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Mathematics 18 Online
OpenStudy (anonymous):

Determine if there is a value for c which makes the function continuous on R2. h(x,y) = {c + y, if x less/equal 3 { 5-x, x>3

OpenStudy (anonymous):

The way to think about these is to realize that if the function is going to be continuous, it must provide the same result for either rule... so (c+y) must be equal to (5-x) at that x=3 point where the rule shifts.

OpenStudy (anonymous):

Except the way this function is written, I'm not sure that's the best approach. I'll think about it for a bit...

OpenStudy (anonymous):

but since 5-x can't equal 3, theres no value of c that would make it continuous?

OpenStudy (anonymous):

maybe... at x less than 3, the function value doesn't even depend on values of x. At x greater than 3, the function value doesn't depend on y

OpenStudy (anonymous):

I think this is like a horizontal line on one side and a vertical line on the other. Weird problem

OpenStudy (anonymous):

hmmm .. soo thinking no value that makes it continuous?

OpenStudy (anonymous):

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OpenStudy (anonymous):

That's what I'm thinking, but I'm still a bit confused by it. Sorry, seemed easy at first glance, and got more weird as I re-read it.

OpenStudy (anonymous):

so .. would (3,5) be the value? possibly ... i guess, hmm

OpenStudy (anonymous):

Oh aack... I got that drawing all backward :(

OpenStudy (anonymous):

Good news is I got myself unconfused... hang on, I'll draw it again. :)

OpenStudy (anonymous):

|dw:1348507969919:dw|

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