Question

the 2 stands for "squared" in the following equation:
g(t) = at2-a2t
find g(-1/2) and g(a)

Answer 1

So a(t^2) - (a^2)t ?

Answer 2

Helloo?
If that's right, then
g(-1/2)=a(-1/2)^2-(a^2)(-1/2) = (a/4)+(a^2/2)

Answer 3

wait
im trying to figure out how to review the whole chat lol

Answer 4

i guess i have to hit post every time?

Answer 5

yea. These are like threads.

Answer 6

ohh okay, so basically i just plug everything in?
sorry im very new to this, thanks for your patience

Answer 7

yea g(a) -> replace all ts with as
g(-1/2) -> replace all ts with (-1/2)

Answer 8

how did you get 0 g(a)

Answer 9

g(a) = a*a^2-a^2*a=a^3-a^3 = 0

Answer 10

Now you'll have to hover your mouse over my profile pic and click on Become a fan, and add a testimonial describing whether I was helpful or not. And also click on the Best Response button if my response helped.

Answer 11

hahahahah

Answer 12

ill do anything you want for helping me lol. i dont have nayone to help me out with this stuff so if you dont mind if like to keep comin back

Answer 13

next time ill be better prepared. right now we're learning ranges of domain and functions of F

Answer 14

lol ofc not. And if I'm not around, there're plenty of others who can help you out

Answer 15

by the way if you need to ask a new question, you will need to close this one, on the left where you asked, there's a close button.

Answer 16

And then you'll be able to ask a new question. If your question is lost below all the new ones, you can hit bump, and that will bump your question up to the top.

Answer 17

Good luck and enjoy OS

Answer 18

thanks but hon that top problem, ow did you get ato the third power?

Answer 19

a^3 *

Answer 20

a^2*a = a^2*a^1=a^(2+1)=a^3

Answer 21

same base, different powers. When you multiply two numbers, you add their powers (if they have the same base)

Answer 22

hah! i understand

Answer 23

so basically boils down to a^3-a^3, right?

Answer 24

yea