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OpenStudy (anonymous):
potassium benzoate, C6H5CO2K, can be prepared from benzyl alcohol, C6H5CH2OH and KMnO4 in aqueous KOH. The manganese is converted to MnO2. balance the equation. I know that redox is used to solve this. can someone just get me started on what i need to do to set up the half reactions. i'm taking orgo and it's been a while...
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OpenStudy (anonymous):
can give me the clear reaction pls
OpenStudy (anonymous):
3C6H5CH2OH+4KMnO4--->3C6H5CO2K+4H2O+KOH+4MNO2 this is the correct answer i think. i just need to see the steps to understand it.
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