Question

okay, soo, i have a equation here that i can't seem to get the right answer for, please help !
(square root of 2x+5)-(square root of x-1)=(square root of x+2).
i don't know how to make the square root sign on my keyboard sorry, please help !

Answer 1

\[\sqrt{2x+5}-\sqrt{x-1}=\sqrt{x+2}\]

Answer 2

\[\sqrt{2x+5}-\sqrt{x-1}=\sqrt{x+2}\]

Answer 3

yes there is the formula, please help me!

Answer 4

square both sides but don't distribute what do you get?

Answer 5

\[(\sqrt{2x+5}-\sqrt{x-1})^2=x+2\]?

Answer 6

\[(\sqrt{2x+5}-\sqrt{x-1})^{2}=x\]

Answer 7

right?

Answer 8

x+2

Answer 9

but yes

Answer 10

x+2 sorry, miss type

Answer 11

now lets write the square root in power form, i think that will help

Answer 12

\[(2x+5)^{1/2}-(x-1)^{1/2})^2=x+2\]

Answer 13

hmm, okay i see what you did there

Answer 14

ehh that looks a little more worst lets just go back and workt the foil out with square roots

\[(\sqrt{2x+5}-\sqrt{x-1})(\sqrt{2x+5}-\sqrt{x-1})\]

Answer 15

we know
\[(a-b)^2=a^2-2ab+b^2\]

Answer 16

yes, squaring a binomial, the 3 step rule

Answer 17

square the first term, multiply the first and second to get the second term then double it, then square the last term

Answer 18

foiling you get

\[2x+5-2(\sqrt{2x+5})(\sqrt{x-1})+x-1=x+2\]

Answer 19

i think i can answer this question, i just need you to verify a few things with me first.

Answer 20

ok

Answer 21

for an example when you have \[(2\sqrt{2x+5}-x+2)(2\sqrt{2x+5-x+2})\] and you are simplfilying and multiplying it through, would the first part of it be \[4\sqrt{4x ^{2}+20x+25}\] ?

Answer 22

oops, the second one isn't supposed to have a radical over everything, just the 2x+5 like the first one

Answer 23

yeah

Answer 24

that would be how to multiply