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Mathematics 19 Online
OpenStudy (anonymous):

The eight grade class at a grage school has 12 girls and 10 boys. How many different boy-girls dates can be arrange?

OpenStudy (anonymous):

it depends on how many hot ppl there are lol

OpenStudy (aripotta):

lol

OpenStudy (anonymous):

???

OpenStudy (anonymous):

12 different girls can date 10 different boys each. 12 x 10 = 120

OpenStudy (aripotta):

@JakeV8 you changed your picture :c

OpenStudy (anonymous):

It's a much different problem if you are talking about how many specific date combinations can a class create at one time, like at a school dance. But it doesn't sound like that's what is being asked.

OpenStudy (anonymous):

@AriPotta yep, keep 'em guessing, that's me. :)

OpenStudy (anonymous):

Is 120 the right answer?

OpenStudy (anonymous):

Ari, Ari Potta, care to weigh in on the math here?

OpenStudy (anonymous):

@lovejones2012 I think so... let's get a 2nd opinion

OpenStudy (aripotta):

hmm. that's what i got too. i'm not great in this probability or whatever. but my first thought was to multiply 12 and 10 too

OpenStudy (anonymous):

These look like "hard" probability problems at first glance, but I think they are more straightforward. It isn't asking for typical probability things like "without replacement" or "order of occurrence" and that stuff.... Think this really is as easy as 12 girls x 10 boys = 120 date combinations

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