Question

I dont know what formula to use:

a car traveling initially at 7.0m/s accelerates uniformly at the rate of 0.80m/s^2 for a distance of 245m
-what is its velocity at the end of the acceleration?
-what is its velocity after it accelerates for 125m
-what is its velocity after it accelerates for 67m?

Answer 1

\[V = u + at\]

\[V^2 - u^2 = 2as\]

Answer 2

V1 = 7m/s
A = .8m/s²
d = 245 m
- v2 = ?
v2² = v1² + 2ad

Answer 3

a car traveling initially at 7.0m/s accelerates uniformly at the rate of 0.80m/s^2 for a distance of 245m
v= velocity after traveling a distance s
u=initial velocity
a=acceleration
s=distance traveled
\[\large v^2-u^2=2as\]
u=7.0 m/s
a=0.80 m/s^2
s=245 m
Let's plugin the values
\[\large v^2-(7)^2=2\times 0.80\times 245\]
now find v from this, to find other parts change the value of s