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The limit represents the derivative of a function f at a number c. Determine f and c.
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lim[(3+h)^2-9]/h as h-->0
any guesses for this one?
See is 9 right?
C
actually no, \(c=3\)
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\(f(x)=x^2\) \[f(3)=3^2=9\] \[\frac{f(3+h)-f(3)}{h}=\frac{(3+h)^2-9}{h}\]
Ah, ok thanks. It makes sense when I look at it laid out like that. I was just thinking that since the numerator ends with f(c) (for the definition of derivative formula) that 9 must have been c.
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