Question

verify (cosBcotB)/(a-sinB) - 1= cscB

Answer 1

wrtie CotB= cosB/SinB

Answer 2

i did

Answer 3

then simply and bring Sin B to denominator , and inside the brackets, and subtract one from fraction and simply, you shall have the answer

Answer 4

post your work, so its easy to identify if it has errors

Answer 5

cos2B/(sinB-sin2B) -1 then what

Answer 6

its shoud be cos^B/(a*Sin B-Sin^2 B) -1

Answer 7

i see you missed the 'a'

Answer 8

did you type the question correctly?

Answer 9

yes its verify the identities

Answer 10

(cosBcotB)/(a-sinB) - 1= cscB is what you typed, what happened to "a" in denominator

Answer 11

\[= \cos ^{2}B - (\sin B - \sin ^{2}) /(\sin B - Sin^2 B)\]

Answer 12

that is where i am stuck

Answer 13

= cos^2 B +sin^2 B-Sin B / (sin B-sin^2 B)

Answer 14

=1-sin B / (sin B) (1-Sin B)= 1/Sin B = cosec B = : )

Answer 15

so 1-sinB/(sinB-sin2B)

Answer 16

happy ?

Answer 17

hello are you there ?