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If 3:sqrt(t^2)+2sqrt(t^3) find f'(t)
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\[f(x)=\sqrt{t^2}+2\sqrt{t^3}\]?
the first square root is ^3
oooh
\[\sqrt[3]{t^2}+2\sqrt{t^3}\]
\[\sqrt[3]{t^2}+\sqrt{t^3}\] maybe
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got it rewrite as \[t^{\frac{2}{3}}+2t^{\frac{3}{2}}\] and use the almighty power rule (once for each term)
2/3t^(-1/3)+3t^(1/2)
yup
thanks!
yw might want to write as \[\frac{2}{3\sqrt[3]{t}}+3\sqrt{t}\]
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oh okay thanks.
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