Question

verify (sinx)/(cscx) -1 = sinxcot(-x)cos(-x)

Answer 1

did you do any work ?

Answer 2

yes

Answer 3

pls show your steps

Answer 4

(sinx)/(cscx) - (cscx)/(cscx)

Answer 5

(sinX-cscx)/(cscx)

Answer 6

= sin^2 x -1= -cos^2x

Answer 7

now simplify right side of equation

Answer 8

how did u get that

Answer 9

sin^x + cos^x=1, so sin^x-1= - cos^2 x

Answer 10

how did u get cosx

Answer 11

or the 1

Answer 12

i just gave the identity

Answer 13

i know but we can't use that identity

Answer 14

who said that

Answer 15

all necesary steps have been show, if a^2+b^2=1 , then a^2-1= -b^2

Answer 16

what i meant was where did u use that identity

Answer 17

well you had sin x / cosec x - cosec x / cosec x= sin x * sin x -1, as cosec x = 1/sin x

Answer 18

i think this is not true

Answer 19

it is absolutely true, but for the lack of efforts shown, anyways work from right side of equation and you will have -cosx * -cos x = -cos^2 x

Answer 20

on the right side i got (six -cscx)/cscx then wht do i do

Answer 21

sin x / cot (-x) = -cos x
cot(-x)=-cot x BUT cos(-x)= cos(x)

Answer 22

sorry i got the right side but not the left side

Answer 23

how can i get (sinx-cscx)/cscx to equal -cos^2 x