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f(x)=h(x)-(3x/h(x)) h(1)=1 h ' (1)=1 Find f ' (1)
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use quotient rule to differentiate f(x) and then put x=1
I'm applying only the quotient rule? To the fraction? I get (3h(x)-3xh'(x)/h(x)^2)
how u got that ? f'(x)= h'(x) - (...*quotient rule here*...)
Si h'(x)-[(h(x)*3]-[3x*h'(x)]/h(x)^2
yup, now put x=1
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Ahh, gotcha.
good :)
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