The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(x). Find each of the following: u'(1)= v'(1)=
ho ho ho have fun actually this is not that hard, lets do one
you pick it
number one is 1. however, I can't figure #2
idea is this \(f'(1)\) is the slope of the line at \(x=1\) it looks like \(f(1)=2\) right?
yea
and \(g'(1)=-\frac{3}{2}\) if i am reading the graph correctly also \(f(1)=g(1)=2\) for sure
so \((\frac{f}{g})'=\frac{gf'-fg'}{t^2}\) replace \(f\) and \(g\) by \(2\), \(f'\) by 1 and \(g'\) by \(-\frac{3}{2}\) and do the annoying arithmetic
typo there, of course it should be \[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\]
I got -3/2
i cant do that arithmetic, but i assume you are correct
its wrong :/
actually maybe not \(g'(1)=-\frac{3}{2}\)
2*1-2*(-3/2)/2^2 right?
\[\frac{2\times 1+\frac{3}{2}\times 2}{2^2}\]
5/2
\[\frac{2+3}{4}=\frac{5}{4}\] is what i get
nope, thats wrong.
damn arithmetic is a killer
:/
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