Question

how do i solve this 5(x-6)/7=3x+4 **the 5(x-6) is over 7**

Answer 1

I'd start by multiplying both sides by 7:

5(x-6)=21x+28

Answer 2

Then distribute that 5 on the left side:
5x-30=21x+28

Answer 3

And from here, we can just combine terms:
5x-2=21x

Answer 4

and even further, -2=16x

Answer 5

So now you just divide both sides by 16, and you get 1/8 = x

Answer 6

Sorry, -1/8 = x

Answer 7

5(x-6)
----- = 3x +4
7
/\/\/\/\/\/\/\//\/\/\/\/\/\//\/\/\/
Distribute:
5x-30
----- = 3x +4
7
/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/
make both sides fraction:

5x-30 3x +4
----- = ---------
7 1

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/
cross multiply

1(5x-30) = 7(3x+4)

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

distribute
5x-30 = 21x+28

/\/\/\/\/\/\/\/\/\/\/\/\
make it to where x is only on one side of the equation by subtracting 5x from both sides.
5x-30 = 21x+28
-5x -5x

-30 = 16x +28
/\/\/\/\/\/\/\/\/\/\/\/\/

isolate the number glued to the variable (16x) by subtracting 28 from both sides.
-30 = 16x +28
-28 -28

-58 = 16x

/\/\/\/\/\/\/\/\/\/

divide both sides by the number glued to the variable (16)

-29
---- = x
8



...this doesn't seem like a decent answer....perhaps I had an error?

Answer 8

Lets see koby's way instead:

5(x-6)
----- = 3x +4
7

/\/\/\/\/

5(x-6)
7/1 { ----- } = 7(3x +4)
7
/\/\/\/\
on the left of the equal the 7 cancels out...
5(x-6) = 7(3x +4)
/\/\/\/\/\/\/
distribute
5x-30 = 21x+28
/\////\/\/\/\/\/\/\/
lets add 30 to both sides.
5x-30 = 21x+28
+30 -30

5x =21x -2
/\/\/\/\/\/\/\/
then subtract 21x from both sides
5x =21x -2
-21x -21x

-16x = -2
/\/\/\/\/\
divide both sides by -16
-16x = -2
---- = ----
-16 -16

x = 1/8