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Integrate the following tan(3x)^2 * sec(3x)^3 dx .... I'm sure there's some sort of identity I'm not remembering/seeing... I would know what to do if sec had an even power...or if tan had an odd power....
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\[tan^2x=sec^2x-1\]
\[tan^2 3x=sec^2 3x -1\]
\[\int\limits (\sec^5(3x) - \sec^3(3x))dx\] Is there a quick way to get to the answer without using reduction forms? Because aren't supposed to use them....
Annnnnnnnyone know? Made it through all the other problems on my assignment, and this is the only one I'm having trouble with.
derivative of tan is sec^2 , so
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