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prove that cos(2s)=2cos^2s - 1
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\[\cos (s+s) = \cos(s).\cos(s) - \sin(s) . \sin(s) = \cos^2(s) - \sin^2 (s)\]
\[\sin^2 (s) + \cos^2 (s) = 1 \]
\[\sin^2 (s) = 1- \cos^2 (s)\]
\[\cos^2 (s) - ( 1 - \cos^2(s) ) = 2\cos^2 (s) - 1\]
how about the identity 1-2sin^2s?
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\[\cos^2 (s) = 1-\sin^2(s)\]
\[1 - \sin^2 (s) - \sin^2(s) = 1- 2\sin^2 (s)\]
ahhh i see Im beginning to get it
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