Question

The x-intercepts of f(x) = sin (x + π/4) are

Answer 1

to get x-intercept we take f(x) = 0
sin ( x+ pi/4) = 0
x+ pi/4 =0

Answer 2

0 and π/4 be the answer

Answer 3

i think u have to expand that

Answer 4

i dont think so
recheck your answer

Answer 5

i think it is pie/4

Answer 6

its two answers because iam working with trig inverses

Answer 7

\[\it's -\frac{ \Pi }{ 4 }\]

Answer 8

\[\sin (x + \Pi/4) = \frac{ sinx }{ \sqrt{2} } +\frac{ cosx }{ \sqrt{2} }\]

Answer 9

\[\frac{ sinx + \cos x }{ \sqrt{2} } = 0\]

Answer 10

\[sinx + \cos x = 0\]

\[\cos^2 x + \sin^2 x = 1\]

\[\cos x = \sqrt{1-\sin^2x}\]

Answer 11

\[sinx = -\sqrt{1-\sin^2x}\]

squaring

\[\sin^2 x = 1- \sin^2x\]

\[2\sin^2 x = 1\]

\[sinx = \frac{ 1 }{ \sqrt{2} }\]

Answer 12

we don't have to complicate this
\[f(x)=0=\sin (x+\frac \pi 4)\]
so
\[x+\frac \pi 4=n\pi\]
where n=0,1, 2, 3, 4
so
\[x=n\pi-\frac \pi 4\]
now we can find the x- intercepts
for n=0
\[x=-\frac \pi 4\]
for n=1
\[x=\frac {3\pi} 4\]
and so on
@timtim do you understand this?

Answer 13

yes i have an idea

Answer 14

good, now change the value of n and find x intercepts. If you get stuck or get any doubts, do ask me.

Answer 15

Yup...@ash2326 ...) an Easy one.... from u..)