Question

(2-y / y squared -y - 6 ) - (4 - y / 12 -y - y squared)

Answer 1

\[[(2-y) \div y ^{2}-3y+2y-6] + [(4-y)\div y ^{2}+y-12]\]

Answer 2

[(2-y) / (y-3)(y+2)] + [(4-y)/ (y+4)(y-3)]
taking L.c.m
[(2-y)(y+4) + (4-y)(y+2)] / [(y-3)(y+2)(y+4)]

Answer 3

i get what u mean tnx

Answer 4

2y+8-y^2-4y+4y+8-y^2-2y / [(y-3)(y+2)(y+4)]
sum up numerator
-y^2 +16/ [(y-3)(y+2)(y+4)]
taking "-" common from numerator
- (y^2-16) / [(y-3)(y+2)(y+4)]
- (y+4)(y-4)/ [(y-3)(y+2)(y+4)]
-(y-4)/ [(y-3)(y+2)]

Answer 5

tnx

Answer 6

No problem :)

Answer 7

is the answer \[\frac{ -2y ^{2} + 16 }{ (y+2)(y-3)(y+4) }\] ?

Answer 8

yes

Answer 9

alrighty!