At a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters. If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas pressure to remain constant?

A. 140 K

B. 273 K

C. 560 K

D. 5600 K

Question

At a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters. If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas pressure to remain constant?

A. 140 K	

B. 273 K	

C. 560 K	

D. 5600 K

anonymous · Answer

Thank you!

anonymous · Answer

I am Sorry There was a mistake in my calculation..i just Found it nw

PV = n R T

P = (n R T1) /V1

P =  (n R T2) / V2

comparing


T1/V1 =  T2/V2

anonymous · Answer

T2 = T1/V2 * V1

anonymous · Answer

So...That the Answer Would be 140K