Question

What is the equation in standard form of a perpindicular line that passes through (5,1)

Answer 1

perpendicular to what?

Answer 2

I don't know it passes through 5.1 though. Algebra is confusing

Answer 3

there are an infinite number of lines passing through \((5,1)\)
i am sure there is another part to this question
perpendicular to the line blah blah
perpendicular to the x axis
perpendicular to the y axis
perpendicular to something

"perpendicular" means two lines make a right angle, so it is a comparison to something

Answer 4

Is there a slope given?

Answer 5

Nope that was the full question. So far I got y-1=m(x-5)

Answer 6

Are you sure there isn't any other information given? An equation? A line?

Answer 7

Nope.

Answer 8

y = (-1/m)(x-5) + 1, given the equation of the original line is y = mx + b. Simply just take the negative reciprocal of m for the slope.

Answer 9

Ok ya so confused.

Answer 10

Then, (y-1)/(x-5) = -1/m. Rearrange into slope-intercept form. Now, you're done!

Answer 11

If you're still confused, just ask a question and maybe I can guide you through it.

Answer 12

Well the next ones ants the x intercept of it and that's gonna be kindofhard to figure for me.

Answer 13

Just take the answer, y = (-1/m)(x-5) + 1, set y=0, and solve for x. The x-intercept takes the form (a,0). You've got the equation now. The value for x will be expressed in terms of m.

Answer 14

ax + by +c and wq of a line perpendicular to it is bx - ay + c

Answer 15

Note : Product of their Slopes m1*m2 = -1

Answer 16

You see, your original question never gave the equation of the "original" line. So, if the question is complete and is to make sense, it logically follows that they are talking about a line in general. So, you have the leeway to say that whatever line you are taling about in the beginning, it has the form of y=mx + b. And that's how I derived the answer.

Answer 17

If you are still confused, just ask a question and I'll walk you through it.