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OpenStudy (anonymous):
how fast should a man of 70 kg run so that his kinetic energy is 875J ?
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OpenStudy (anonymous):
@ganeshie8 help please !
OpenStudy (anonymous):
\[K.E = \frac{ 1 }{ 2 }* m*v^2\]
OpenStudy (anonymous):
875 = 1/2 * 70 * v^2 v^2 = 25 v = 5m/s
OpenStudy (anonymous):
@Yahoo! ty :)
OpenStudy (anonymous):
Welcome..)
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