Question

A bullet of mass 50 g is moving with velocity 500 m/s . It penetrates 10m into a still target and comes to rest . Calculate (A) the KE possessed by the bullet (B) the avg. retarding force offered by the target .

Answer 1

@Yahoo!

Answer 2

\[K.E = \frac{ 1 }{ 2 } m * v^2\]

Answer 3

and (B) ?

Answer 4

Hint: Convert Mass gram to Kg

Answer 5

For b u have to Find the Acceleration :

\[v^2 - u^2 = 2as\]

Answer 6

V = 0 Since the Bullet Comes to Rest

Answer 7

and U is 500 ?

Answer 8

\[K.E = \frac{ 1 }{2 } * 50 * 10^{-3} * 500 * 500\]

Answer 9

\[V^2 - u^2 = 2as\]

\[a = \frac{ u^2 }{ 2s }\]

Answer 10

\[a= \frac{ 500 * 500 }{ 2 * 10 }\]

Answer 11

After Finding a

\[F = M*a\]

Answer 12

hope...this helps u..)

Answer 13

what is the meaning of avg. retarding force ?

Answer 14

just force ?

Answer 15

@yahoo there ?

Answer 16

It is Just Force..)

Answer 17

okay , ty :)

Answer 18

Welcome...)