Question

.

Answer 1

first I think it is 4/2

Answer 2

i also got a different answer. cos(pi/2) is 0 sin(pi/2) is 1

Answer 3

I would cancel out the cos(pi/2) first then distribute and apply sin(pi/2) = 1 to get your simplified answer.

Answer 4

but doesnt 2pi/3 - pi/2 = pi/6?

Answer 5

that is correct. I don't know where you subtract in this problem tho.

Answer 6

ohhh im sorry i meant to post the same exact question but it was in division

Answer 7

I got \[2(i \cos \frac{ 2\pi }{ 3 }+\sin \frac{ 2\pi }{ 3 })\]

Answer 8

oh ok. repost and I'll recheck

Answer 9

http://i729.photobucket.com/albums/ww292/akatushi101/img9.gif

Answer 10

same answer right?

Answer 11

i'll be back in 20. but redo it because 1/2 divided by 4 is 1/8

Answer 12

ok

Answer 13

1/8(cos pi/6 + i sin pi/6)?

Answer 14

can you convert the trig function to the value in radians in order to get the soln

Answer 15

my answer should be in that format.

Answer 16

I guess my question is... Is the a certain way we r supposed to solve this

Answer 17

no its not for solving but more as simplifying it

Answer 18

i got \[-\frac{ \sin \frac{ 2\pi }{ 3 } }{ 16 }\]

Answer 19

cos pi/2 = 0

Answer 20

sin pi/2 = 1

Answer 21

so you have 1/2 (cos 2pi/3 + i sin 2pi/3) over 4 i

Answer 22

ok

Answer 23

I'm wrong

Answer 24

\[\frac{ -\frac{ 1 }{ 2 } +isin \frac{ 2\pi }{ 3 }}{ 8i }\]

Answer 25

hopefully you see this because I brought the -1/2 down and you are not allowed to.