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Mathematics 11 Online
OpenStudy (anonymous):

stats help needed...

OpenStudy (anonymous):

OpenStudy (anonymous):

i need help with part A

OpenStudy (anonymous):

i dont know what to do after i get the z-score... which is -0.966 (when rounded)

OpenStudy (anonymous):

@estudier @myininaya @phi @sasogeek @Tyler1992

OpenStudy (anonymous):

@bahrom7893

OpenStudy (anonymous):

like what is the next step? i have the zscore and i have the graph drawn out (68-95-99.7)

OpenStudy (bahrom7893):

You look it up in the z-table. Sorry I'm bad at stat, hang around while help comes.

OpenStudy (anonymous):

@ash2326 @Jemurray3

OpenStudy (bahrom7893):

@amistre64 @satellite73

OpenStudy (bahrom7893):

@Libniz

OpenStudy (phi):

look in you z table for the area above -0.966 std dev. it looks like about 83 %

OpenStudy (anonymous):

can you show me the work? im confused on the last steps

OpenStudy (anonymous):

like how would i solve it without using Excel or something like that

OpenStudy (phi):

You would use a z-table or calculator Do you use a table ?

OpenStudy (anonymous):

i dont know what a z table is to be frank

OpenStudy (phi):

Here is a site that does the conversion http://www.tutor-homework.com/statistics_tables/statistics_tables.html How are you doing these problems?

OpenStudy (anonymous):

this is the first one like this on my hw

OpenStudy (phi):

your book must talk about how to do this?

OpenStudy (phi):

but to do a) select standard distribution (the first one shown) right tail type in -0.966 for z and have it calculate the area under the curve to the right of that z score. that is the chance the weight is above this z score

OpenStudy (anonymous):

any way this can be done on a graphing calc rather than on this site?

OpenStudy (phi):

if it knows about normal distributions (do they?) otherwise http://en.wikipedia.org/wiki/Normal_distribution#Numerical_approximations_for_the_normal_CDF is a (messy) way

OpenStudy (anonymous):

using normal since ur z score is -0.966 round to 2 decimal u'll have -0.97 it means u'll have P(z>=-0.97) because it is over 1050 u'll have 1-P(Z<=-0.97) on the z table -0.97 it hase the probability of 0.1660 now 1-(0.1660) 0.834 wich by conclusion is 83.4%

OpenStudy (anonymous):

do u get it?

OpenStudy (anonymous):

yeah i get everything except the part where i get the 0.1660. i dont know how to get it without using the site Phi gave me above. ^^^

OpenStudy (anonymous):

check this tables

OpenStudy (anonymous):

do u see -0.97 ?

OpenStudy (anonymous):

yes i get that by doing the formula for z score and rounding

OpenStudy (anonymous):

do u see the value that correspond to it ?

OpenStudy (anonymous):

not really no. i dont get how that part works.

OpenStudy (anonymous):

|dw:1348601547745:dw| the deshes represents some numbers on the table ;right

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