Question

Find the real solutions of the equation.
(x+1)^2+16(x+1)+63=0

Answer 1

is the equation:
\[(x+1)^{2}+6(x+1)+63=0\]?

Answer 2

(x+1)2+16(x+1)+63=0*

Answer 3

I would start out by distributing the 16, figuring out (x+1)^2, and combining like terms to put the equation in standard form.

Answer 4

(x+1)2+16(x+1)+63=0
\[au^{2}+bu+c=0\]
u^2= (x+1)
u^2+16u+63=0

Answer 5

(x+1)2+16(x+1)+63=0
Let's start with the 16(x+1)
What would that look like after distributing it?

Answer 6

It's okay, I find the answer: {-10,-8}.