Question

Okay people, I need help with Quadratic equations, i.e. \[ax^{2}+bx+c=0\]

I have 5 and i will only put 1 here. so keep up!

Answer 1

Sounds easy enough. DO you know the Quadratic formula?

Answer 2

\[4x^{2}+9x+2-0\]
I know that the answer is:
\[x=\frac{ -9\pm \sqrt{81-4(4)(2)} }{ 8 }\]

Answer 3

How do i get from point A to point B? aka from the equation to the answer

Answer 4

yea, thats what it says in my book. I do the Life of Fred series and i am doing Quadratic Equation.

Answer 5

rly? its that easy?!?!?!?!?! omfg!

Answer 6

Take it a step further and come up with two different answers android. I believe in you.

Answer 7

how are ther two different answers?

Answer 8

Honestly, ill say it in the 3 different launguages i know.
English:no
Spanish:no
ASL:shankes head

Answer 9

ik but, i don't get how you got them. how do you go from\[-9\pm \frac{ \sqrt{81-32} }{ 8 } \to -9\pm \frac{\sqrt{49} }{ 2 } \]

Answer 10

For

\[ax^2+bx+c=0=4x^2+9x+2\]
\[a=4,b=9,c=2\]
using the quadratic formula

\[x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\]

substituting in
\[a=4,b=9,c=2\]
\[x=\frac{-9\pm \sqrt{9^2-4(4)(2)}}{2(4)}\]
\[x=\frac{-9\pm \sqrt{81-32}}{8}\]
\[x=\frac{-9 \pm \sqrt{49}}{8}\]
\[x=\frac{-9\pm 7}{8}\]
\[x=\frac{-9+7}{8}\]
\[x=\frac{-2}{8}=\frac{-1}{4}\]
and
\[x=\frac{-9-7}{8}\]
\[x=\frac{-16}{8}=-2\]

Answer 11

okay, delete that long post and spearate the posts by a \[\to\] that get put into each other so its easier to read.