Use Coulomb’s Law to determine the magnitude and direction of the electric field EB at
point B in the diagram due to the two positive charges (Q = 7.0 μC). If a proton is located
at point B, calculate the magnitude and direction of the force F acting on the proton.

Question

Use Coulomb’s Law to determine the magnitude and direction of the electric field EB at
point B in the diagram due to the two positive charges (Q = 7.0 μC). If a proton is located
at point B, calculate the magnitude and direction of the force F acting on the proton.

ketz · Answer

attachment

ketz · Answer

Urgent answer needed!! (I've exams tomorrow)

anonymous · Answer

Do you understand vector notation?

anonymous · Answer

it shows the direction of vector quantity...

ketz · Answer

What about the magnitude?

noelgreco · Answer

$$E=k \frac{ Q }{ r ^{2} }$$
Calculate the magnitude of the electric field at point B

anonymous · Answer

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anonymous · Answer

E1 has the same direction as r1
E2 has the same direction as r2
find the magnitudes of each field in terms of Q
find the 'x' and 'y' components of each field
add the 'y' components; add the x components : those sums are the components of the net field

anonymous · Answer

any questions about that?

anonymous · Answer

@Algebraic! PLEASE MAKE IT MORE CLEARER

anonymous · Answer

what part?

anonymous · Answer

finding magnitudes of E?

anonymous · Answer

E1:    (9E9*7E-6)/.005m


etc

anonymous · Answer

YEA..I WAS THINK THE 2 CHARGES WILL ADD UP ALGEBRAICALLY AND THE RESULTANT WILL HAVE EFFECT ON THE TEST CHARGE PROTON

anonymous · Answer

direction of E1 : angle is 45   so E1x = ((9E9*7E-6)/.005m) *cos(45)
                                                         E1y =((9E9*7E-6)/.005m) *sin(45)

(edited: now with more parentheses!!_

anonymous · Answer

PLS HOW DID THE ANGLE BECOME 45 DEGREES

anonymous · Answer

well...

anonymous · Answer

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