Mathematics
18 Online
OpenStudy (anonymous):
Approximate the volume of a spherical shell where the inner radius is 4 inches and whose thickness is 1/16 inches using DIFFERENTIALS.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hi. do you still need help with this problem?
OpenStudy (anonymous):
yes. will you help me?
OpenStudy (anonymous):
i will do what i can, yes
OpenStudy (anonymous):
so let's start off with whether or not we can find some applicable formulas here.
OpenStudy (anonymous):
your heaven sent thank you..:)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
do you have the answer to this thing?
OpenStudy (anonymous):
none..
OpenStudy (anonymous):
k. Let's start with what we know. Like maybe the volume of a sphere.
OpenStudy (anonymous):
Do you remember the formula for the volume of a sphere? dont worry, you are gonna get through this problem. I promise
OpenStudy (anonymous):
(pi)(d)^3/6
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
or 4/3 (pi) R^3
OpenStudy (anonymous):
yes... that is what we seek..
OpenStudy (anonymous):
now what is the variable that affects the volume? Because that is the variable that will drive the differentiation process.
OpenStudy (anonymous):
Radius?
OpenStudy (anonymous):
absolutely.. good. Now how do we get the differential of this little puppy?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
solve for V' ?
OpenStudy (anonymous):
what is it we are approximating?
OpenStudy (anonymous):
wait. i didnt see the prime
OpenStudy (anonymous):
the volume of a spherical shell
OpenStudy (anonymous):
yes. we want V'
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so how does one go about getting V'?
OpenStudy (anonymous):
in reality, it is dV/dr we need.
OpenStudy (anonymous):
\[\frac{ dv }{ dr }=(\frac{ 4 }{ 3 })(\pi)(3R)\]
not sure..is it right?
OpenStudy (anonymous):
you are very close. check the exponent on the R term
OpenStudy (anonymous):
3R^2 :)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes. so the whole differential looks like.... dV=
OpenStudy (anonymous):
remember that dV=(dV/dr)dr
OpenStudy (anonymous):
dv = (4/3)(pi)(3R^2)dr ?
OpenStudy (anonymous):
perfect!
OpenStudy (anonymous):
notice how the 3's cancel
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
for somebody who desperately thought you could nt do this problem, you are doing remarkably well :)
OpenStudy (anonymous):
dv = 4 pi R^2 dr
OpenStudy (anonymous):
yes. now plug in your given values and u are done. excellent work
OpenStudy (anonymous):
notice how you can approximate the change in volume by taking the product of the surface area of the sphere and dr.
OpenStudy (anonymous):
where do i substitute 4 inches to? 1/16 inches?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
r=4 and dr=1/16
OpenStudy (anonymous):
dv = 12.5663... ?
OpenStudy (anonymous):
this approximation is good because the dr or differential of r is very small ( 1/16)
OpenStudy (anonymous):
ummm... i dont have a calc with me. but that looks pretty close to 4pi, which is the answer i got
OpenStudy (anonymous):
thank you (1000000000x)!!!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
it was such a pleasure
OpenStudy (anonymous):
wait one last question...
OpenStudy (anonymous):
sure. shoot.
OpenStudy (anonymous):
find the value of cos 43 using differentials...
OpenStudy (anonymous):
lol. i think i saw that problem an hour or two ago.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes..but no one helped me :(
OpenStudy (anonymous):
i am so sorry. i saw someone looking so i decided to move on.
OpenStudy (anonymous):
ok. the drill is the same....except... ummm... slightly different. and no, that is not a DIFFERENTial joke.
OpenStudy (anonymous):
so where do you think you might start? what is the reference angle you would use in this case? 43 degrees is very close to .....
OpenStudy (anonymous):
45 degrees
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
good. that is exactly correct
OpenStudy (anonymous):
what function are we differentiating?
OpenStudy (anonymous):
cos
OpenStudy (anonymous):
y=....
OpenStudy (anonymous):
nice
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
now i could be mistaken, but i think we need to do this in radians
OpenStudy (anonymous):
so? what's the next step?
OpenStudy (anonymous):
find the formula for the differential given that y=cos x
OpenStudy (anonymous):
dy/dx = -sin x ?
OpenStudy (anonymous):
perfect. and so dy=?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
-sin x dx
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
x=? dx?
OpenStudy (anonymous):
no, dy=-sin x dx
OpenStudy (anonymous):
i mean
what is x=?
dx=?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
x=45=pi/4 and dx=-2=-pi/90
OpenStudy (anonymous):
why -pi/90?
OpenStudy (anonymous):
cuz that is 2 degrees in radians. all trig function are calculated in radians in calc. cant remember for the life of me why tho. sorry about that
OpenStudy (anonymous):
(-2)xpi/180=-pi/90. the pi/180 converts degrees to radians
OpenStudy (anonymous):
remember that dx=delta x=43-45=-2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ahh..gets
OpenStudy (anonymous):
if you are not comfy cozy with this, please feel free to ask me questions
OpenStudy (anonymous):
is dx= change in x?
OpenStudy (anonymous):
yes, by the definition of a differential. the differential of y, dy, equals y'x dx, where dx=the change in x
OpenStudy (anonymous):
oops.. the differential of y still equals y'x dx, not y'x dx.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hmmm
OpenStudy (anonymous):
y'dx
OpenStudy (anonymous):
there we go
OpenStudy (anonymous):
oh okay...thanks a lot again!!
i hope you'll never get tired of helping me..
see ya next time??
OpenStudy (anonymous):
i hope so. it has been a pleasure. you take care unk. lol. bye