Question

Quadratic Equation question

How do i get from:
\[x=-11\pm \frac{121-60}{ 6 }\]
to the next part?

Answer 1

@jwheele1

Answer 2

ok

Answer 3

im working on those problems too im not that good but i would simplify 121-6/ then.. which is?

Answer 4

well first of all.....write out two different equations to eliminate that +-

Answer 5

@cos00155079 you doing the Life of Fred series?

Answer 6

you don't have to do that @jwheele1

Answer 7

i know you dont have to but its easier...its cool we wont do that then

Answer 8

the what? nooo...

Answer 9

121 - 60 = ?

Answer 10

61

Answer 11

10

Answer 12

\[1\]
\[-21\]

Answer 13

why 60/6 if it was a 61?

Answer 14

ik

Answer 15

alright lets see now...

Answer 16

the equation is:
\[x=-11\pm \frac{ \sqrt{121-60} }{ 6 } \]

Answer 17

oh lawd....lol

Answer 18

sq rt of 121 = 11

Answer 19

whats with teh line over the 0?

Answer 20

its just how it is. not my doing.

Answer 21

well...it means that its a repeating number but its usually only after a decimal point...weird.

Answer 22

I have no idea what to do with the 60 and the line over it.

Answer 23

the original equation is:
\[3x^{2}+11x+5=0\]

Answer 24

any specific way she is wanting you to go about that?

Answer 25

its a messup about square roots.

Answer 26

or can we solve for x any old way?

Answer 27

yea, using \[ax^{2}+bx+c=0\] and the
\[x=-b\pm\frac{ \sqrt{b^{2}-4ac} }{ 2a }\]

Answer 28

the QuAdRaTiC ForMulA.....lol

Answer 29

ok so

3x^2 + 11x +5 = 0

ax^2 + bx +c

Answer 30

a = 3
b = 11
c = 5

Answer 31

\[-11\pm \frac{ \sqrt{11^{2}-4(3*5c)} }{ 2(3) }\]

Answer 32

does that look right?

Answer 33

ignore the c next to the 5, lol