A catapult launches a boulder with an upward velocity of 112 ft/s. The height of the boulder, h, in feet after t seconds is given by the function h= -16t^2 + 112t + 30 . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.
A. 7 s; 30 ft B. 3.5 s; 366 ft C. 3.5 s; 618 ft D. 3.5 s; 226 ft
is this precal
use the vertex formula
@baldymcgee6 how do I do that
-b/2a
can u use calculator
D
D. 3.5 s; 226 ft
i am sure
WIth the calculator what would I divide or Minus?
is this for a calculus class or not?
i think it is not @baldymcgee6
you don't know what class you're in? haha
Its Algebra 2
r u adressing me
use calculator
find max point
How @ksaimouli, i wrote everything into the calculator and I got -114 that is not correct answer
-b/2a = -112/2(16) = 3.5 s t= 3.5s h = -16t^2 + 112t + 30 h = -16(3.5)^2 +122(3.5) +30 h = 226
adjust the windows to y=300
@chicagochica5 i told you how, use the vertex formula, and this will give you the time at which it is at its maximum
say 2nd and calc and press find max
@ksaimouli, Just I have a phone calculator
@baldymcgee6 is that formula used in calculus
@chicagochica5 it is better to do it by hand, @ksaimouli is suggesting you use a graphing calculator, which is totally possible and easier, but it doesn't help you learn and sometimes you are not allowed a calculator.
no u should have ti-83
yup u r right
@ksaimouli some classes do not allow a graphing calculator such as the ti 83, and no it definitely not a calculus formula.
but i confuses when we say another and their teacher says totally different
its simply a parabolic formula to find the vertex of a parabola.
Thanks @ksaimouli and @baldymcgee6
welcome
you are welcome @chicagochica5
Join our real-time social learning platform and learn together with your friends!