Question

Integral ((x)/(x^(2)+1)

Answer 1

Use u-substitution to get the answer.

Answer 2

\[\large \int \frac{x}{x^2+1}dx\]Let u = x^2+1, then du=\(2xdx\); \(\frac{1}{2}du=xdx\)\[\large \frac{1}{2}\int\frac{1}{u}du\]

Answer 3

The answer i got is (1/2)ln(x^(2)+1) + C but for some reason its not right.

Answer 4

That looks correct for me.\[\large =\frac{1}{2}ln|x^2+1|+C\]
I used absolute value since that's how I learned that.

Answer 5

alright thank you

Answer 6

np.