assume there are 4 grey females, 4 grey males, 2 white females, and 3 white males. As in the book, the biologist selects two mice randomly. (1) What is the probability of selecting two males given that both are grey? (2) What is the probability of selecting 1 mouse of each gender given that both are grey?
please help!!!
there are 4 grey males and how many total?
oh damn i answered some other question i should learn how to read, ignore that post
for (1) I believe it is 4/8*3/7
thats not right
or 4C2/8C2
like 4 choose 2 over 8 choose 2?
yep
thats not right
put \(A\) as the event both chosen are males, \(B\) as the event both chosen are grey, and then compute \[P(A|B)=\frac{P(A\cap B)}{P(B)}\]
\[P(B)=\frac{8}{13}\times \frac{7}{12}=\frac{14}{39}\]
14/39 isn't right
yes, it is not right, we are not done we still have to compute \(P(A\cap B)\) \(A\cap B\) is the event both chosen are grey males, it is \[\frac{4}{13}\times \frac{3}{12}\]
better known as \[\frac{1}{13}\]
so your answer should be \[\frac{P(A\cap B)}{P(B)}=\frac{\frac{1}{13}}{\frac{14}{39}}=\frac{1}{13}\times \frac{39}{14}=\frac{3}{14}\]
that's exactly the same as 4C2/8C2
that is right!! do u know how to do the second part?
@pizzapi that is probably a snappier way of doing it, yes
but he/she said it was wrong
maybe less intuitive, but definitely quicker
how do you do the second part
(4C1*4C1)/(8C2)
thanks!!
hold phone, that one might not be right
Assume that the box contains 11 balls: 4 red, 4 blue, and 3 yellow. As in the text, you draw one ball, note its color, and if it is yellow replace it. If it is not yellow you do not replace it. You then draw a second ball and note its color. (1) What is the probability that the second ball drawn is yellow? (2) What is the probability that the second ball drawn is red?
do you know how to do that?
yes but hold on a second
part 2 was right.. my homework tells you right off when you enter if correct
yes, it is right i had a brain freeze last problem you posted is harder and we have to work through it step by step
ok
a nice tree diagram might help let me see if i can draw one, because it is hard for me to draw here |dw:1348627260493:dw|
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